Optimal. Leaf size=641 \[ -\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {\sqrt {2} b e^{7/4} f p \log \left (-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{7 d^{7/4} h^{9/2}}+\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}+1\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{5/4} g p \log \left (-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{5 d^{5/4} h^{9/2}}+\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{5 d^{5/4} h^{9/2}}+\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}+1\right )}{5 d^{5/4} h^{9/2}}-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}} \]
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Rubi [A] time = 0.83, antiderivative size = 641, normalized size of antiderivative = 1.00, number of steps used = 25, number of rules used = 11, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.379, Rules used = {2467, 2476, 2455, 325, 211, 1165, 628, 1162, 617, 204, 297} \[ -\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {\sqrt {2} b e^{7/4} f p \log \left (-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{7 d^{7/4} h^{9/2}}+\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}+1\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{5/4} g p \log \left (-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{5 d^{5/4} h^{9/2}}+\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}+\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x\right )}{5 d^{5/4} h^{9/2}}+\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}+1\right )}{5 d^{5/4} h^{9/2}}-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}} \]
Antiderivative was successfully verified.
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Rule 204
Rule 211
Rule 297
Rule 325
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 2455
Rule 2467
Rule 2476
Rubi steps
\begin {align*} \int \frac {(f+g x) \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{(h x)^{9/2}} \, dx &=\frac {2 \operatorname {Subst}\left (\int \frac {\left (f+\frac {g x^2}{h}\right ) \left (a+b \log \left (c \left (d+\frac {e x^4}{h^2}\right )^p\right )\right )}{x^8} \, dx,x,\sqrt {h x}\right )}{h}\\ &=\frac {2 \operatorname {Subst}\left (\int \left (\frac {f \left (a+b \log \left (c \left (d+\frac {e x^4}{h^2}\right )^p\right )\right )}{x^8}+\frac {g \left (a+b \log \left (c \left (d+\frac {e x^4}{h^2}\right )^p\right )\right )}{h x^6}\right ) \, dx,x,\sqrt {h x}\right )}{h}\\ &=\frac {(2 g) \operatorname {Subst}\left (\int \frac {a+b \log \left (c \left (d+\frac {e x^4}{h^2}\right )^p\right )}{x^6} \, dx,x,\sqrt {h x}\right )}{h^2}+\frac {(2 f) \operatorname {Subst}\left (\int \frac {a+b \log \left (c \left (d+\frac {e x^4}{h^2}\right )^p\right )}{x^8} \, dx,x,\sqrt {h x}\right )}{h}\\ &=-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {(8 b e g p) \operatorname {Subst}\left (\int \frac {1}{x^2 \left (d+\frac {e x^4}{h^2}\right )} \, dx,x,\sqrt {h x}\right )}{5 h^4}+\frac {(8 b e f p) \operatorname {Subst}\left (\int \frac {1}{x^4 \left (d+\frac {e x^4}{h^2}\right )} \, dx,x,\sqrt {h x}\right )}{7 h^3}\\ &=-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}}-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}-\frac {\left (8 b e^2 g p\right ) \operatorname {Subst}\left (\int \frac {x^2}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{5 d h^6}-\frac {\left (8 b e^2 f p\right ) \operatorname {Subst}\left (\int \frac {1}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{7 d h^5}\\ &=-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}}-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}-\frac {\left (4 b e^2 f p\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d} h-\sqrt {e} x^2}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{7 d^{3/2} h^6}-\frac {\left (4 b e^2 f p\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d} h+\sqrt {e} x^2}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{7 d^{3/2} h^6}+\frac {\left (4 b e^{3/2} g p\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d} h-\sqrt {e} x^2}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{5 d h^6}-\frac {\left (4 b e^{3/2} g p\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d} h+\sqrt {e} x^2}{d+\frac {e x^4}{h^2}} \, dx,x,\sqrt {h x}\right )}{5 d h^6}\\ &=-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}}-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {\left (\sqrt {2} b e^{7/4} f p\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h}}{\sqrt [4]{e}}+2 x}{-\frac {\sqrt {d} h}{\sqrt {e}}-\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}-x^2} \, dx,x,\sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}+\frac {\left (\sqrt {2} b e^{7/4} f p\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h}}{\sqrt [4]{e}}-2 x}{-\frac {\sqrt {d} h}{\sqrt {e}}+\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}-x^2} \, dx,x,\sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}-\frac {\left (\sqrt {2} b e^{5/4} g p\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h}}{\sqrt [4]{e}}+2 x}{-\frac {\sqrt {d} h}{\sqrt {e}}-\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}-x^2} \, dx,x,\sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}-\frac {\left (\sqrt {2} b e^{5/4} g p\right ) \operatorname {Subst}\left (\int \frac {\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h}}{\sqrt [4]{e}}-2 x}{-\frac {\sqrt {d} h}{\sqrt {e}}+\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}-x^2} \, dx,x,\sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}-\frac {\left (2 b e^{3/2} f p\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {d} h}{\sqrt {e}}-\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}+x^2} \, dx,x,\sqrt {h x}\right )}{7 d^{3/2} h^4}-\frac {\left (2 b e^{3/2} f p\right ) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {d} h}{\sqrt {e}}+\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}+x^2} \, dx,x,\sqrt {h x}\right )}{7 d^{3/2} h^4}-\frac {(2 b e g p) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {d} h}{\sqrt {e}}-\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}+x^2} \, dx,x,\sqrt {h x}\right )}{5 d h^4}-\frac {(2 b e g p) \operatorname {Subst}\left (\int \frac {1}{\frac {\sqrt {d} h}{\sqrt {e}}+\frac {\sqrt {2} \sqrt [4]{d} \sqrt {h} x}{\sqrt [4]{e}}+x^2} \, dx,x,\sqrt {h x}\right )}{5 d h^4}\\ &=-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}}-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}-\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x+\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}+\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x+\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}-\frac {\left (2 \sqrt {2} b e^{7/4} f p\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}+\frac {\left (2 \sqrt {2} b e^{7/4} f p\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}-\frac {\left (2 \sqrt {2} b e^{5/4} g p\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}+\frac {\left (2 \sqrt {2} b e^{5/4} g p\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}\\ &=-\frac {8 b e f p}{21 d h^3 (h x)^{3/2}}-\frac {8 b e g p}{5 d h^4 \sqrt {h x}}+\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}+\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{7/4} f p \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{7 d^{7/4} h^{9/2}}-\frac {2 \sqrt {2} b e^{5/4} g p \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{e} \sqrt {h x}}{\sqrt [4]{d} \sqrt {h}}\right )}{5 d^{5/4} h^{9/2}}-\frac {2 f \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{7 h (h x)^{7/2}}-\frac {2 g \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )}{5 h^2 (h x)^{5/2}}+\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}-\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x-\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}-\frac {\sqrt {2} b e^{7/4} f p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x+\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{7 d^{7/4} h^{9/2}}+\frac {\sqrt {2} b e^{5/4} g p \log \left (\sqrt {d} \sqrt {h}+\sqrt {e} \sqrt {h} x+\sqrt {2} \sqrt [4]{d} \sqrt [4]{e} \sqrt {h x}\right )}{5 d^{5/4} h^{9/2}}\\ \end {align*}
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Mathematica [C] time = 0.07, size = 100, normalized size = 0.16 \[ -\frac {2 \sqrt {h x} \left (3 d (5 f+7 g x) \left (a+b \log \left (c \left (d+e x^2\right )^p\right )\right )+20 b e f p x^2 \, _2F_1\left (-\frac {3}{4},1;\frac {1}{4};-\frac {e x^2}{d}\right )+84 b e g p x^3 \, _2F_1\left (-\frac {1}{4},1;\frac {3}{4};-\frac {e x^2}{d}\right )\right )}{105 d h^5 x^4} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.27, size = 1369, normalized size = 2.14 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.38, size = 488, normalized size = 0.76 \[ -\frac {\frac {6 \, {\left (5 \, \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} b f h p e^{\frac {11}{4}} + 7 \, \sqrt {2} \left (d h^{2}\right )^{\frac {3}{4}} b g p e^{\frac {9}{4}}\right )} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\left (-\frac {1}{4}\right )} + 2 \, \sqrt {h x}\right )} e^{\frac {1}{4}}}{2 \, \left (d h^{2}\right )^{\frac {1}{4}}}\right ) e^{\left (-1\right )}}{d^{2} h} + \frac {6 \, {\left (5 \, \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} b f h p e^{\frac {11}{4}} + 7 \, \sqrt {2} \left (d h^{2}\right )^{\frac {3}{4}} b g p e^{\frac {9}{4}}\right )} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\left (-\frac {1}{4}\right )} - 2 \, \sqrt {h x}\right )} e^{\frac {1}{4}}}{2 \, \left (d h^{2}\right )^{\frac {1}{4}}}\right ) e^{\left (-1\right )}}{d^{2} h} + \frac {3 \, {\left (5 \, \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} b f h p e^{\frac {11}{4}} - 7 \, \sqrt {2} \left (d h^{2}\right )^{\frac {3}{4}} b g p e^{\frac {9}{4}}\right )} e^{\left (-1\right )} \log \left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\left (-\frac {1}{4}\right )} + h x + \sqrt {d h^{2}} e^{\left (-\frac {1}{2}\right )}\right )}{d^{2} h} - \frac {3 \, {\left (5 \, \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} b f h p e^{\frac {11}{4}} - 7 \, \sqrt {2} \left (d h^{2}\right )^{\frac {3}{4}} b g p e^{\frac {9}{4}}\right )} e^{\left (-1\right )} \log \left (-\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\left (-\frac {1}{4}\right )} + h x + \sqrt {d h^{2}} e^{\left (-\frac {1}{2}\right )}\right )}{d^{2} h} + \frac {2 \, {\left (84 \, b g h^{4} p x^{3} e + 20 \, b f h^{4} p x^{2} e + 21 \, b d g h^{4} p x \log \left (h^{2} x^{2} e + d h^{2}\right ) - 21 \, b d g h^{4} p x \log \left (h^{2}\right ) + 15 \, b d f h^{4} p \log \left (h^{2} x^{2} e + d h^{2}\right ) - 15 \, b d f h^{4} p \log \left (h^{2}\right ) + 21 \, b d g h^{4} x \log \relax (c) + 21 \, a d g h^{4} x + 15 \, b d f h^{4} \log \relax (c) + 15 \, a d f h^{4}\right )}}{\sqrt {h x} d h^{3} x^{3}}}{105 \, h^{5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.86, size = 0, normalized size = 0.00 \[ \int \frac {\left (g x +f \right ) \left (b \ln \left (c \left (e \,x^{2}+d \right )^{p}\right )+a \right )}{\left (h x \right )^{\frac {9}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.08, size = 557, normalized size = 0.87 \[ -\frac {b e f p {\left (\frac {3 \, {\left (\frac {\sqrt {2} e^{\frac {3}{4}} \log \left (\sqrt {e} h x + \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\frac {1}{4}} + \sqrt {d} h\right )}{\left (d h^{2}\right )^{\frac {3}{4}}} - \frac {\sqrt {2} e^{\frac {3}{4}} \log \left (\sqrt {e} h x - \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\frac {1}{4}} + \sqrt {d} h\right )}{\left (d h^{2}\right )^{\frac {3}{4}}} + \frac {2 \, \sqrt {2} e \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {1}{4}} + 2 \, \sqrt {h x} \sqrt {e}\right )}}{2 \, \sqrt {\sqrt {d} \sqrt {e} h}}\right )}{\sqrt {\sqrt {d} \sqrt {e} h} \sqrt {d} h} + \frac {2 \, \sqrt {2} e \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {1}{4}} - 2 \, \sqrt {h x} \sqrt {e}\right )}}{2 \, \sqrt {\sqrt {d} \sqrt {e} h}}\right )}{\sqrt {\sqrt {d} \sqrt {e} h} \sqrt {d} h}\right )}}{d} + \frac {8}{\left (h x\right )^{\frac {3}{2}} d}\right )}}{21 \, h^{3}} - \frac {b e g p {\left (\frac {e {\left (\frac {2 \, \sqrt {2} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {1}{4}} + 2 \, \sqrt {h x} \sqrt {e}\right )}}{2 \, \sqrt {\sqrt {d} \sqrt {e} h}}\right )}{\sqrt {\sqrt {d} \sqrt {e} h} \sqrt {e}} + \frac {2 \, \sqrt {2} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {1}{4}} - 2 \, \sqrt {h x} \sqrt {e}\right )}}{2 \, \sqrt {\sqrt {d} \sqrt {e} h}}\right )}{\sqrt {\sqrt {d} \sqrt {e} h} \sqrt {e}} - \frac {\sqrt {2} \log \left (\sqrt {e} h x + \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\frac {1}{4}} + \sqrt {d} h\right )}{\left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {3}{4}}} + \frac {\sqrt {2} \log \left (\sqrt {e} h x - \sqrt {2} \left (d h^{2}\right )^{\frac {1}{4}} \sqrt {h x} e^{\frac {1}{4}} + \sqrt {d} h\right )}{\left (d h^{2}\right )^{\frac {1}{4}} e^{\frac {3}{4}}}\right )}}{d} + \frac {8}{\sqrt {h x} d}\right )}}{5 \, h^{4}} - \frac {2 \, b g x^{2} \log \left ({\left (e x^{2} + d\right )}^{p} c\right )}{5 \, \left (h x\right )^{\frac {9}{2}}} - \frac {2 \, a g x^{2}}{5 \, \left (h x\right )^{\frac {9}{2}}} - \frac {2 \, b f \log \left ({\left (e x^{2} + d\right )}^{p} c\right )}{7 \, \left (h x\right )^{\frac {7}{2}} h} - \frac {2 \, a f}{7 \, \left (h x\right )^{\frac {7}{2}} h} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {\left (f+g\,x\right )\,\left (a+b\,\ln \left (c\,{\left (e\,x^2+d\right )}^p\right )\right )}{{\left (h\,x\right )}^{9/2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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